(3y-1)(y^2+5y-4)=

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Solution for (3y-1)(y^2+5y-4)= equation: 


Simplifying
(3y + -1)(y2 + 5y + -4) = 0

Reorder the terms:
(-1 + 3y)(y2 + 5y + -4) = 0

Reorder the terms:
(-1 + 3y)(-4 + 5y + y2) = 0

Multiply (-1 + 3y) * (-4 + 5y + y2)
(-1(-4 + 5y + y2) + 3y * (-4 + 5y + y2)) = 0
((-4 * -1 + 5y * -1 + y2 * -1) + 3y * (-4 + 5y + y2)) = 0
((4 + -5y + -1y2) + 3y * (-4 + 5y + y2)) = 0
(4 + -5y + -1y2 + (-4 * 3y + 5y * 3y + y2 * 3y)) = 0
(4 + -5y + -1y2 + (-12y + 15y2 + 3y3)) = 0

Reorder the terms:
(4 + -5y + -12y + -1y2 + 15y2 + 3y3) = 0

Combine like terms: -5y + -12y = -17y
(4 + -17y + -1y2 + 15y2 + 3y3) = 0

Combine like terms: -1y2 + 15y2 = 14y2
(4 + -17y + 14y2 + 3y3) = 0

Solving
4 + -17y + 14y2 + 3y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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